Comments on: Solving ActionScript Puzzlers in PowerShell

By: Paul Chavez

Paul Chavez — Fri, 22 Jan 2010 17:17:33 +0000

I see, in your example you don’t have an else statement when checking for existence of $caps. Since I have the else something gets added to $result in any case.

By: Doug Finke

Doug Finke — Thu, 21 Jan 2010 22:06:57 +0000

I believe the second time thru when searching for $name and the value is not found, $f is -eq $null. This gets appended to your $result array, causing the count ot be 2.

You can check it like this: $result[1] -eq $null

By: Paul Chavez

Paul Chavez — Thu, 21 Jan 2010 17:26:20 +0000

This looked suspiciously like a quick ‘zip’ function I wrote last night so I tried to see if the issue applied to my logic. It doesn’t act exactly the same but is still odd. Here is a sample:
——-
function loopy2
{

$names = “abc”,”def”
$names2 = “def”,”ghi”
$result = @()
$names2 | ForEach-Object {
$name = $_
$f = $names | ?{ $_ -eq $name }

if ($f) { $result += $f.ToUpper() }
else { $result += $f }
}
$result.count
}
——-
I output the count property of the array because if it worked correctly you’d expect one item in the array, but really there ends up being two. However the second value is empty string or $null or something, not “def” as you might expect from the puzzle results.